(x^2)+36x=49

Solution for (x^2)+36x=49 equation:

(x^2)+36x=49

We move all terms to the left:

(x^2)+36x-(49)=0

a = 1; b = 36; c = -49;
Δ = b2-4ac
Δ = 362-4·1·(-49)
Δ = 1492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1492}=\sqrt{4*373}=\sqrt{4}*\sqrt{373}=2\sqrt{373}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{373}}{2*1}=\frac{-36-2\sqrt{373}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{373}}{2*1}=\frac{-36+2\sqrt{373}}{2}
$